How do you factor the trinomial 49 - 4x^249−4x2?

1 Answer
Meave60
Nov 23, 2015

7^2-(2x)^2=(7+2x)(7-2x)72−(2x)2=(7+2x)(7−2x)

Explanation:

49-4x^249−4x2 represents a difference of squares, in which a^2-b^2=(a+b)(a-b)a2−b2=(a+b)(a−b), where a=7 and b=2xa=7andb=2x.

7^2-(2x)^2=(7+2x)(7-2x)72−(2x)2=(7+2x)(7−2x)

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