How do you factor the trinomial $5x^2 - 3x - 26 = 0$ ?

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Answer 1 · 2016-02-04T02:38:40

It is $(x+2)*(5x-13)=0$

You can factor this as follows

$5x^2-3x-26=0=>5x^2+(10)x-13x-26=0=> 5x(x+2)-13(x+2)=0=>(x+2)*(5x-13)=0$

How do you factor the trinomial 5x^2 - 3x - 26 = 05x^2 - 3x - 26 = 0?