How do you factor the trinomial $5 x^{2} + 5 x - 10$ $5x^2 + 5x - 10$ ?

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Answer 1 · 2016-03-16T22:07:47

$5 (x + 2) (x - 1)$ $5(x+2)(x-1)$

Let us understand the standard form of a trinomial.

$a x^{2} + b x + c$ $ax^2+bx+c$

In this case, 5 is the $a$ $a$ term, 5 is the $b$ $b$ term, and -10 is the $c$ $c$ term.

All of these terms have one term in common-- 5. We can divide each term in this trinomial by 5, and multiply it to the overall equation.

$5 (x^{2} + x - 2)$ $5(x^2+x-2)$

Now there is a simple trinomial inside the parentheses.

We must find two numbers that multiply to -2 and add to 1. These are +2 and -1.

Write these as binomials

$5 (x + 2) (x - 1)$ $5(x+2) (x-1)$

This is your final answer.

How do you factor the trinomial 5x2+5x−105x^2 + 5x - 10 ?