How do you factor the trinomial $6x^2 -51x-63$ ?

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Answer 1 · 2015-12-02T14:46:52

Factor $y = 6x^2 - 51x - 63$

$y = 6x^2 - 51x - 63$
$D = b^2 - 4ac = (51)^2 + 4(6)(63) = 2601 + 1512 = 4113.$
D is not a perfect square, therefor, the trinomial can't be factored.

How do you factor the trinomial 6x^2 -51x-636x^2 -51x-63?