How do you factor the trinomial $6x^2 +8x-9$ ?

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Answer 1 · 2016-02-29T04:50:24

Can't be factored.

D = b^2 - 4ac = 64 + 216 = 280
Since D is not a perfect square, this trinomial can't be factored.

How do you factor the trinomial 6x^2 +8x-96x^2 +8x-9?