How do you factor the trinomial $6y ^2 + 72y + 192 = 0$ ?

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Answer 1 · 2015-12-19T22:40:52

$6(y+8)(y+4)$

The trinomial can be simplified by factoring out $6$

You then have the following:

$6(y^2+12y+32)=0$

This should make things easier to factor

Now find two numbers that when added together equal $12$ and when multiplied equal $32$

How do you factor the trinomial 6y ^2 + 72y + 192 = 06y ^2 + 72y + 192 = 0?