How do you factor the trinomial $7x^2-71x+10$ ?

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Answer 1 · 2016-01-17T00:33:55

$7x^2-71x+10 = (7x-1)(x-10)$

Look for a pair of factors of $AC=7*10 = 70$ with sum $B=71$ .

The pair $70, 1$ works.

Use that to split the middle term and factor by grouping:

$7x^2-71x+10$

$=(7x^2-70x)-(x-10)$

$=7x(x-10)-1(x-10)$

$=(7x-1)(x-10)$

How do you factor the trinomial 7x^2-71x+107x^2-71x+10?