How do you factor the trinomial $8b^2-5b-10$ ?

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Answer 1 · 2015-11-23T04:39:25

Factor $f(b) = 8b^2 - 5b - 10$

$f(b) = 8b^2 - 5b - 10.$
$D = b^2 - 4ac = 25 + 320 = 345$ .
Since D is not a perfect square, this trinomial can't be factored.

How do you factor the trinomial 8b^2-5b-10 8b^2-5b-10 ?