How do you factor the trinomial $9 - 10 x + x^{2}$ $9-10x+x^2$ ?

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Answer 1 · 2018-06-02T08:04:32

$(x - 9) (x - 1)$ $(x-9)(x-1)$

Solving
$x^{2} - 10 + 9 = 0$ $x^2-10+9=0$ we get
$x_{1, 2} = 5 \pm \sqrt{25 - 9}$ $x_{1,2}=5pmsqrt(25-9)$
so
$x_{1} = 9$ $x_1=9$
$x = 1$ $x=1$

How do you factor the trinomial 9−10x+x29-10x+x^2?