How do you factor the trinomial $9t-22+t^2$ ?

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Answer 1 · 2016-06-03T07:55:28

$(t-2)(t+11)$

To comply with convention write as

$t^2+9t-22$

Consider the factors of 22 as being 2 and 11.

Also observe that $11-2=9$

So we have:

$(t-2)(t+11)$

How do you factor the trinomial 9t-22+t^29t-22+t^2?