How do you factor the trinomial $a^2 - 12a +32 = 0$ ?

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Answer 1 · 2018-04-06T15:34:02

a = 4, 8.

Given, $a^2-12a+32 = 0$
$rArr a^2-4a-8a+32=0$
$rArr a(a-4)-8(a-4)=0$
$rArr (a-4)(a-8)=0$
$rArr (a-4)=0,(a-8)=0$
$rArr a=4,8$

How do you factor the trinomial a^2 - 12a +32 = 0 a^2 - 12a +32 = 0?