How do you factor the trinomial # a^2 - 12a +32 = 0#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer Nityananda Apr 6, 2018 a = 4, 8. Explanation: Given, #a^2-12a+32 = 0# #rArr a^2-4a-8a+32=0# #rArr a(a-4)-8(a-4)=0# #rArr (a-4)(a-8)=0# #rArr (a-4)=0,(a-8)=0# #rArr a=4,8# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2934 views around the world You can reuse this answer Creative Commons License