How do you factor the trinomial $a^{2} - 14 a b + 24 b^{2}$ $a^2-14ab+24b^2$ ?

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How do you factor the trinomial $a^{2} - 14 a b + 24 b^{2}$ $a^2-14ab+24b^2$ ?

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Answer 1 · 2015-12-10T03:14:06

Factor $y = a^{2} - 14 a b + 24 b^{2}$ $y = a^2 - 14ab + 24b^2$

Ans: (a - 2b)(a - 12b)

Explanation:

$y = a^{2} - 14 a b + 24 b^{2} .$ $y = a^2 - 14ab + 24b^2.$
Find 2 numbers knowing sum (-14b) and product (24b^2). Factor pairs of (24b^2) --> (2b, 12b). This sum is 14b. Then the opposite sum gives 2 numbers: -2b and -12b.
Factored form: $y = (a - 2 b) (a - 12 b)$ $y = (a - 2b)(a - 12b)$

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How do you factor the trinomial $a^{2} - 14 a b + 24 b^{2}$ $a^2-14ab+24b^2$ ?

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How do you factor the trinomial $a^{2} - 14 a b + 24 b^{2}$ $a^2-14ab+24b^2$ ?