How do you factor the trinomial $b^2 + 12b + 32$ ?

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Answer 1 · 2018-08-04T01:19:39

$(b + 4) (b + 8)$

$b^2 + 12b + 32$

Using Factorization Method..

The factors are;

$4 and 8$

$12b = 4b + 8b$

$32 = 4 xx 8$

Hence;

$b^2 + 4b + 8b + 32$

Grouping;

$(b^2 + 4b) (8b + 32)$

$b(b + 4) +8(b + 4)$

$(b + 4) (b + 8) -> "Factorized"$

Answer 2 · 2018-08-05T01:34:01

$(b+8)(b+4)$

Let's do a little thought experiment:

What two number sum up to $12$ (middle term) and have a product of the last term $(32)$ ?

After some trial and error, we arrive at $8$ and $4$ . This means we can factor this business as

$(b+8)(b+4)$

Hope this helps!

How do you factor the trinomial b^2 + 12b + 32b^2 + 12b + 32?