How do you factor the trinomial $j^2+22j+40$ ?

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Answer 1 · 2016-02-16T18:42:23

$j^2+22j+40 = color(green)((j+2)(j+20))$

[Note: I edited the question to make it "22j" instead of just "22"; hope this was what was intended].

$(j+a)(j+b)=j^2+(a+b)j+ab$

So in order to write $j^2+22j+40$ as the product of two binomials,
we want to find values $a$ and $b$ such that
$a+b=22$ and $axxb=40$

How do you factor the trinomial j^2+22j+40 j^2+22j+40?