How do you factor the trinomial $k^{2} - 27 k j - 90 j^{2}$ $k ^2 - 27kj - 90j ^2$ ?

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How do you factor the trinomial $k^{2} - 27 k j - 90 j^{2}$ $k ^2 - 27kj - 90j ^2$ ?

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Answer 1 · 2016-06-22T00:24:53

$(k - 30 j) (k + 3 j)$ $(k-30j)(k+3j)$

Explanation:

To factor $k^{2} - 27 k j - 90 j^{2}$ $k^2-27kj-90j^2$

Begin by finding the factors of $90$ $90$
$1 & 90$ $1 & 90$
$2 & 45$ $2&45$
$3 & 30$ $3&30$
$5 & 18$ $5&18$
$6 & 15$ $6&15$
$9 & 10$ $9&10$

Now look at the signs of the trinomial. Since the second sign is negative we need to subtract the factors to get the middle term $27$ $27$ . The signs of the binomials will need to be $- & +$ $- & +$

This means we will use $30 & 3$ $30 &3$

Sine the first sign is negative the larger factor will be negative so we will use $- 30 & + 3$ $-30 & +3$

$(k - 30 j) (k + 3 j)$ $(k-30j)(k+3j)$

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How do you factor the trinomial $k^{2} - 27 k j - 90 j^{2}$ $k ^2 - 27kj - 90j ^2$ ?

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How do you factor the trinomial $k^{2} - 27 k j - 90 j^{2}$ $k ^2 - 27kj - 90j ^2$ ?