How do you factor the trinomial m^2 + 8m + 12?

1 Answer
Mar 15, 2016

m^2+8m+12 = (m+2)(m+6)

Explanation:

Notice that 2+6 = 8 and 2 xx 6 = 12

So: m^2+8m+12 = (m+2)(m+6)

In general, we find:

(m+a)(m+b) = m^2+(a+b)m+ab

So if you have a monic quadratic (one that has a leading coefficient of 1) to factor, typically you are looking for a pair of factors of the constant term with sum or difference equal to the middle coefficient.