How do you factor the trinomial $r^2 + 17r + 72$ ?

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Answer 1 · 2015-11-27T04:39:52

$r^2+17r+72=(r+8)(r+9)$

$r^2+17r+72$

Find two numbers that when added equal $17$ and when multiplied equal $72$ . The numbers $8$ and $9$ meet the criteria.

Rewrite the expression as $(r+8)(r+9)$ .

How do you factor the trinomial r^2 + 17r + 72r^2 + 17r + 72?