How do you factor the trinomial $t^{2} + 3 t - 54 = 0$ $t^2 + 3t - 54 = 0$ ?

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Answer 1 · 2016-02-02T11:47:38

$(t + 9) = 0 or (t - 6) = 0$ $(t+9) = 0 or (t-6) =0$

$t^{2} + 3 t - 54 = 0$ $t^2 + 3t -54 =0$

$t^{2} + 9 t - 6 t - 54 = 0$ $t^2+9t-6t-54=0$

$t (t + 9) - 6 (t + 9) = 0$ $t(t+9) -6(t+9)=0$

$(t + 9) (t - 6) = 0$ $(t+9) (t-6) =0$

$(t + 9) = 0 or (t - 6) = 0$ $(t+9) = 0 or (t-6) =0$

$t = 9 or t = 6$ $t=9 or t=6$

How do you factor the trinomial t2+3t−54=0 t^2 + 3t - 54 = 0?