How do you factor the trinomial $v^3 - 4v^2 - 45v$ ?

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Answer 1 · 2016-04-09T11:17:15

$v(v-9)(v+5)$

Taking $v$ out as a common factor, we get:

$v(v^2-4v-45)$

Now what we have is a quadratic multiplied by a common factor.
Factorising the quadratic we get the fully factored function:

$v(v-9)(v+5)$

How do you factor the trinomial v^3 - 4v^2 - 45vv^3 - 4v^2 - 45v?