How do you factor the trinomial $x^{2} + 11 x - 28$ $x^2 + 11x - 28$ ?

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How do you factor the trinomial $x^{2} + 11 x - 28$ $x^2 + 11x - 28$ ?

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Answer 1 · 2018-04-10T05:42:26

$(x + \frac{11 + \sqrt{233}}{2}) (x - \frac{- 11 + \sqrt{233}}{2})$ $(x+(11+sqrt(233))/2)(x-(-11+sqrt(233))/2)$

Explanation:

$x²+11x-28$
$Delta=11²-4*1*(-28)=121+112=233$
$x1=(-11-sqrt(233))/2$
$x2=(-11+sqrt(233))/2$
So a factorized form of the trinomial is : $(x-(-11-sqrt(233))/2)(x-(-11+sqrt(233))/2)$
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How do you factor the trinomial $x^{2} + 11 x - 28$ $x^2 + 11x - 28$ ?

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How do you factor the trinomial $x^{2} + 11 x - 28$ $x^2 + 11x - 28$ ?