How do you factor the trinomial $x^{2} + 22 x + 72$ $x^2 + 22x + 72$ ?

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How do you factor the trinomial $x^{2} + 22 x + 72$ $x^2 + 22x + 72$ ?

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Answer 1 · 2016-03-19T10:20:14

$\Rightarrow (x + 18) (x + 4)$ $=>(x+18)(x+4)$

Explanation:

$72 = 18 \times 4; 18 + 4 = 22$ $72=18xx4;18+4 =22$
$x^{2} + 22 x + 72$ $x^2+22x+72$
$\Rightarrow x^{2} + 18 x + 4 x + 72$ $=>x^2+18x+4x+72$
$\Rightarrow x (x + 18) + 4 (x + 18)$ $=>x(x+18)+4(x+18)$
$\Rightarrow (x + 18) (x + 4)$ $=>(x+18)(x+4)$

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How do you factor the trinomial $x^{2} + 22 x + 72$ $x^2 + 22x + 72$ ?

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How do you factor the trinomial x2+22x+72x^2 + 22x + 72?

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How do you factor the trinomial $x^{2} + 22 x + 72$ $x^2 + 22x + 72$ ?