How do you factor the trinomial $x^2+ 2x-4$ ?

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Answer 1 · 2018-04-24T00:23:52

The expression $x^2+2x-4$ cannot be factored any further

there are no numbers you can multiply to get negative four and add to get $-2x$

Answer 2 · 2018-04-24T00:26:12

The answer $x_2=-1+sqrt5$ or $x_2=-1-sqrt5$

Follow the steps

$x_1=(-b+sqrt(b^2-4ac))/(2a)$

$x_2=(-b-sqrt(b^2-4ac))/(2a)$

from $x^2+2x-4=0$

$ax^2+bx+c=0$

a=1 b=2 c=-4

$x_1=(-2+sqrt(2^2+16))/(2)$

$x_1=-1+sqrt5$

or in the same way

$x_2=-1-sqrt5$

How do you factor the trinomial x^2+ 2x-4x^2+ 2x-4?