How do you factor the trinomial $x^2- 2x - 8$ ?

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Answer 1 · 2016-03-31T02:21:49

$x^2-2x-8=(x+2)(x-4)$

Select the numbers from the factors of 8
possible factors are 2 and 4 which has a difference of 2 with a product of 8.

God bless....I hope the explanation is useful.

How do you factor the trinomial x^2- 2x - 8 x^2- 2x - 8?