How do you factor the trinomial $x^2+4x-12$ ?

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Answer 1 · 2018-04-20T19:11:51

$x+6)(x-2)$

$"the factors of - 12 which sum to + 4 are + 6 and - 2"$

$rArrx^2+4x-12=(x+6)(x-2)$

How do you factor the trinomial x^2+4x-12x^2+4x-12?