How do you factor the trinomial $x^2-6x-5$ ?

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Answer 1 · 2016-01-29T00:09:18

can't be factored

$D = b^2 - 4ac = 36 + 20 = 56$ .
Since D is not a perfect square, this trinomial can't be factored.

How do you factor the trinomial x^2-6x-5x^2-6x-5?