How do you factor the trinomial $x^2-7x+6$ ?

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Answer 1 · 2018-03-11T13:22:17

$(x-1)(x-6)$

$"factor using the a-c method"$

$"the factors of + 6 which sum to - 7 are - 1 and - 6"$

$rArrx^2-7x+6=(x-1)(x-6)$

Answer 2 · 2018-03-11T13:24:34

$x^2-7x+6=(x-1)(x-6)$

$x^2-7x+6$

First, find two numbers that add up to $-7$ and multiply to give $6$ ,

$-1$ and $-6$ , where these two numbers are roots.

Next, add $x$ to the numbers,

$(x-1)$ and $(x-6)$ , where these two numbers are factors.

Now, factor,

$x^2-7x+6=(x-1)(x-6)$

How do you factor the trinomial x^2-7x+6x^2-7x+6?