How do you factor the trinomial $x^{2} - 8 x + 15$ $x^2 - 8x + 15$ ?

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Answer 1 · 2015-11-28T20:03:00

$(x - 3) (x - 5)$ $(x-3)(x-5)$

Note: $3 \times 5 = + 15$ $3xx5=+15$

$(- 3) \times (- 5) = + 15$ $(-3)xx(-5)=+15$ as well!

$(- 3) + (- 5) = (- 8)$ $(-3)+(-5)=(-8)$

So we have:

$(x - 3) (x - 5) = x^{2} - 3 x - 5 x + 15$ $(x-3)(x-5) = x^2-3x-5x+15$

How do you factor the trinomial x2−8x+15 x^2 - 8x + 15?