How do you factor the trinomial $-x^2 - 8x + 20$ ?

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Answer 1 · 2016-05-24T11:13:15

$-x^2-8x+20=-(x-2)(x+10)$

$-x^2-8x+20=-(x^2+8x-20)$

$x^2+8x-20=(x+10)(x-2)$

$-x^2-8x+20=-(x-2)(x+10)$

How do you factor the trinomial -x^2 - 8x + 20-x^2 - 8x + 20?