How do you factor the trinomial $x^2+9x+8$ ?

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Answer 1 · 2016-01-03T18:00:06

Find two numbers that multiply to term c in $ax^2$ + bx + c and that addd to term b

Two numbers that multiply to 8 and that add up to 9 are 8 and 1, so we have our factors

= (x + 1)(x + 8)

Answer 2 · 2016-01-03T18:11:28

It is

$x^2+9x+8=x^2+x+8x+8=x^2+x+8*(x+1)=x*(x+1)+8*(x+1)=(x+8)*(x+1)$

How do you factor the trinomial x^2+9x+8x^2+9x+8?