How do you factor the trinomial $y^{2} - 7 x y + 10 x^{2}$ $y^2-7xy+10x^2$ ?

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Answer 1 · 2018-03-19T10:51:33

$(y - 2 x) (y - 5 x)$ $(y-2x)(y-5x)$

We can split the $7 x y$ $7xy$ to get:
$y^{2} - 2 x y - 5 x y + 10 x^{2}$ $y^2-2xy-5xy+10x^2$

Then factor out to get:
$y (y - 2 x) - 5 x (y - 2 x)$ $y(y-2x)-5x(y-2x)$

Now we take one set of brackets then also take the coefficients into another:
$(y - 2 x) (y - 5 x)$ $(y-2x)(y-5x)$

How do you factor the trinomial y^2-7xy+10x^2y2−7xy+10x2y^2-7xy+10x^2?