How do you factor the trinomial $y^{2} - 7 y - 8$ $y^2 - 7y - 8$ ?

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Answer 1 · 2015-12-13T05:16:35

Factor $f (y) = y^{2} - 7 y - 8$ $f(y) = y^2 - 7y - 8$ .

Since (a - b + c = 0), use shortcut. The 2 factors are: (x + 1) and
(x + c/a) = (x - 8)
f(y) = (y + 1)(y - 8),.

NOTE. When (a - b + c = 0), the 2 real roots are: -1 and (-c/a = 8).

How do you factor the trinomial y2−7y−8y^2 - 7y - 8?