How do you factor the trinomial $y²-49$ ?

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Answer 1 · 2015-11-27T02:12:13

$(y+7)(y-7)$

This is a difference of squares—the $y^2$ is $(y)^2$ and $49$ is $(7)^2$ .

This is the rule for a difference of squares: $a^2-b^2=(a+b)(a-b)$

Thus, $y^2-49=(y+7)(y-7)$ .

How do you factor the trinomial y²-49y²-49?