How do you factor u^3-2u^2-8u+16u32u28u+16?

2 Answers

Refer to explanation

Explanation:

It is

u^3-2u^2-8u+16=u^2(u-2)-8(u-2)=(u^2-8)(u-2)=(u-sqrt8)(u+sqrt8)(u-2)=(u-2sqrt2)(u+2sqrt2)(u-2)u32u28u+16=u2(u2)8(u2)=(u28)(u2)=(u8)(u+8)(u2)=(u22)(u+22)(u2)

Sep 23, 2015

Try this:

Explanation:

You can collect u^2u2 from the first and third term and -88 from the second and fourth to get:
u^2(u-2)-8(u-2)=u2(u2)8(u2)=
Now collect (u-2)(u2) and get:
=(u-2)(u^2-8)=(u2)(u28)