How do you factor $w^{2} + 4 w + 3$ $w^2+4w+3$ ?

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How do you factor $w^{2} + 4 w + 3$ $w^2+4w+3$ ?

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Answer 1 · 2018-03-07T07:51:07

$(w + 3) (w + 1)$ $(w+3)(w+1)$

Explanation:

In this case, since $a = 1$ $a = 1$ (in $a x^{2} + b x + c$ $ax^2+bx+c$ ), simply look for two numbers whose sum is $4$ $4$ and whose product is $3$ $3$ . You can easily see that the two numbers are $1$ $1$ and $3$ $3$ .

Then, just write it down: $(w + 3) (w + 1)$ $(w+3)(w+1)$

Check: try expanding the brackets using FOIL.

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How do you factor $w^{2} + 4 w + 3$ $w^2+4w+3$ ?

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