How do you factor $x²-10x+21$ ?

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Answer 1 · 2015-11-18T02:28:47

$x^2-10x+21=(x-3)(x-7)$

$x^2-10x+21$

Find two numbers that when added equal $-10$ , and when multiplied equal $21$ .

The numbers $-3$ and $-7$ meet the criteria.

$x^2-10x+21=(x-3)(x-7)$

How do you factor x²-10x+21x²-10x+21?