How do you factor $x^2 +1 - x$ ?

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Answer 1 · 2016-08-26T15:48:32

$x=1/2+-[1/2sqrt(3)]i$

given: $" "x^2-x+1$

The discriminant is: $b^2-4ac -> (-1)^2-4(1)(1) = -3$

AS the discriminant is negative there are no factors for $x^2-x+1=0$ for $x !in RR$ . The graph does not cross the x-axis.

Tony B

$x=(-b+-(sqrt(b^2-4ac)))/(2a)" " ->" " (1+-sqrt((-1)^1-4(1)(1)))/(2(1))$

$x=1/2+-(sqrt(-3))/2$

$x=1/2+-[1/2sqrt(3)]i$

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