How do you factor $x^{2} - 12 x - 45$ $x^2-12x-45$ ?

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How do you factor $x^{2} - 12 x - 45$ $x^2-12x-45$ ?

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Answer 1 · 2016-06-23T21:08:04

$(x - 15) (x + 3)$ $(x-15)(x+3)$

Explanation:

Look at the colour coding to see what each part of the trinomial tells us.

$x^{2} - 12 x - 45$ $x^2 color(blue)(-) color(orange)(12)xcolor(purple)(-)color(red)(45)$

Find the factors of $45$ $color(red)(45)$ which $subtract$ $color(purple)("subtract")$ to give $12$ $color(orange)(12)$ .
The signs will be $different$ $color(purple)("different")$ , there must be more $negatives.$ $color(blue)("negatives.")$
The factors of 45 which we need are 15 and 3.

$15 \times 3 = 45 and 15 - 3 = 12$ $15 xx3 = 45 and15-3 = 12$

$(x - 15) (x + 3)$ $(x-15)(x+3)$

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How do you factor $x^{2} - 12 x - 45$ $x^2-12x-45$ ?

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How do you factor x2−12x−45x^2-12x-45?

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How do you factor $x^{2} - 12 x - 45$ $x^2-12x-45$ ?