How do you factor $x^2 + 17x + 42 =0$ ?

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Answer 1 · 2018-06-26T08:58:49

-3, -14

$x^2 + 17x +42 = 0$
or, $x^2 + 14x + 3x +42 = 0$
or, $x(x + 14) + 3 (x + 14) = 0$
or, $(x + 3)(x+14)$ = 0
or, $x= -3, -14$

Answer 2 · 2018-06-26T09:14:46

$(x+3)(x+14)=0$

$"the factors of " +42" which sum to "+17$
$"are "+3" and "+14$

$x^2+17x+42=0$

$(x+3)(x+14)=0$

How do you factor x^2 + 17x + 42 =0x^2 + 17x + 42 =0?