How do you factor $x^2+1x-12$ ?

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Answer 1 · 2016-12-19T14:52:14

$(x + 4)(x - 3)$

To solve this problem we must play with multipliers for 12 (1x12, 2x6 3x4) which also add to $1$ :

$(x + 4)(x - 3)$

Answer 2 · 2016-12-19T14:53:09

$(x-3)(x+4)$ is the answer

First, multiply $12$ by the coefficient of the square, i.e

$12 * 1 = 12$

Now use two factors of $12$ to get $1x$ either by adding or by subtracting the factors.

$x^2 +x-12$

$=x^2-3x+4x-12$

$=x(x-3)+4(x-3)$

$=(x-3)(x+4)$

How do you factor x^2+1x-12x^2+1x-12?