How do you factor $x^{2} + 33 x - 108$ $x^2 + 33x - 108$ ?

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Answer 1 · 2018-03-03T21:07:13

$x^{2} + 33 x - 108 = (x + 36) (x - 3)$ $x^2+33x-108 = (x+36)(x-3)$

Find a pair of factors of $108$ $108$ which differ by $33$ $33$ .

The pair $36, 3$ $36, 3$ works in that $36 \cdot 3 = 108$ $36 * 3 = 108$ and $36 - 3 = 33$ $36 - 3 = 33$

Hence:

$x^{2} + 33 x - 108 = (x + 36) (x - 3)$ $x^2+33x-108 = (x+36)(x-3)$

How do you factor x2+33x−108x^2 + 33x - 108?