How do you factor $x^{2} - 36 = 0$ $x^2-36=0$ ?

Question

10064 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-17T05:13:43

(x-6)(x+6)

Since

$a^{2} - b^{2} = (a - b) (a + b)$ $a^2-b^2=(a-b)(a+b)$

then you can factor:

$x^{2} - 36 = (x - 6) (x + 6)$ $x^2-36=(x-6)(x+6)$

How do you factor x2−36=0x^2-36=0 ?