How do you factor $x^{2} - 3 x - 10$ $x^2-3x-10$ ?

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Answer 1 · 2016-11-02T08:37:18

$x^{2} - 3 x - 10 = (x - 5) (x + 2)$ $x^2-3x-10 = (x-5)(x+2)$

Given:

$x^{2} - 3 x - 10$ $x^2-3x-10$

Find a pair of factors of $10$ $10$ which differ by $3$ $3$ .

The pair $5, 2$ $5, 2$ works in that $5 \cdot 2 = 10$ $5*2=10$ and $5 - 2 = 3$ $5-2=3$

Hence we find:

$x^{2} - 3 x - 10 = (x - 5) (x + 2)$ $x^2-3x-10 = (x-5)(x+2)$

How do you factor x2−3x−10x^2-3x-10?