How do you factor $x^{2} + 3 x + 4 x + 12$ $x^2+3x+4x+12$ ?

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Answer 1 · 2015-05-11T01:23:12

The factors of $x^{2} + 7 x + 12$ $x^2+7x+12$ are $(x + 3) (x + 4)$ $(x+3)(x+4)$ .

Factor $x^{2} + 3 x + 4 x + 12$ $x^2+3x+4x+12$ .

Simplify $3 x + 4 x$ $3x+4x$ to $7 x$ $7x$ .

$x^{2} + 7 x + 12$ $x^2+7x+12$

Find two numbers that when added will make 7, and when multiplied will make 12. Numbers 3 and 4 make 7 when added and 12 when multiplied.

$(x + 3) (x + 4) = x^{2} + 7 x + 12$ $(x+3)(x+4)=x^2+7x+12$

How do you factor x2+3x+4x+12x^2+3x+4x+12?