How do you factor $(x^{2} - 4 x^{2} - 9 x + 36$ $(x^2-4x^2-9x+36$ ?

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Answer 1 · 2015-05-12T00:35:33

$f (x) = - 3 x^{2} - 9 x + 36) = - 3 (x^{2} + 3 x - 12)$ $f(x) = -3x^2 - 9x + 36) = -3(x^2 + 3x - 12)$

The trinomial in parentheses has D = 9 + 48 = 57. It is not a perfect square, then this trinomial can't be factored.

How do you factor (x^2-4x^2-9x+36(x2−4x2−9x+36(x^2-4x^2-9x+36?