How do you factor $x^2-4x+45$ ?

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Answer 1 · 2015-09-30T00:38:08

It cannot be factored because
the term $sqrt(b^2-4ac)$ is negative.

$x^2−4x+45$

It cannot be factored because
the term $sqrt(b^2-4ac) = sqrt ((-4)^2-(4 xx 1 xx 45)) = sqrt (16-180)$
We cannot find square root for $-164$ .

How do you factor x^2-4x+45x^2-4x+45?