How do you factor $x^{2} - 6 x + 8$ $x^2- 6x+8$ ?

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How do you factor $x^{2} - 6 x + 8$ $x^2- 6x+8$ ?

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Answer 1 · 2015-03-27T00:02:08

You can try by finding two numbers that multiplied give $8$ $8$ and added $- 6$ $-6$ ;
They could be $- 4$ $-4$ and $- 2$ $-2$
So you could write:
$(x - 4) (x - 2) = x^{2} - 2 x - 4 x + 8 = x^{2} - 6 x + 8$ $(x-4)(x-2)=x^2-2x-4x+8=x^2-6x+8$
:-)

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How do you factor $x^{2} - 6 x + 8$ $x^2- 6x+8$ ?

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