How do you factor $x^{2} - 8 x + 16$ $x^2-8x+16$ ?

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How do you factor $x^{2} - 8 x + 16$ $x^2-8x+16$ ?

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Answer 1 · 2015-05-05T00:08:16

I would try to find two numbers that added together give $- 8$ $-8$ and multiplied $16$ $16$ : they can be: $- 4$ $-4$ and $- 4$ $-4$ :
So I can write:

$(x - 4) (x - 4) = {(x - 4)}^{2} = x^{2} - 8 x + 16$ $(x-4)(x-4)=(x-4)^2=x^2-8x+16$

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How do you factor $x^{2} - 8 x + 16$ $x^2-8x+16$ ?

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How do you factor $x^{2} - 8 x + 16$ $x^2-8x+16$ ?