How do you factor x^2 - 8x + 16?

1 Answer
Sep 9, 2016

x^2-8x+16=(x-4)(x-4)=(x-4)^2

Explanation:

To factorize x^2-8x+16, we should split the coefficient of middle term -8 in two parts whose product is product of coefficients of other two terms, i.e. 1xx16=16.

The pair is 4 and 4 and hence

x^2-8x+16

= x^2-4x-4x+16

= x(x-4)-4(x-4)

= (x-4)(x-4)=(x-4)^2