How do you factor $x^2-xy-56y^2$ ?

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Answer 1 · 2016-05-04T20:20:44

$x^2-xy-56y^2 = (x-8y)(x+7y)$

Find a pair of factors of $56$ which differ by $1$ .

The pair $8, 7$ works in that $8xx7=56$ and $8-7=1$

Hence:

$x^2-xy-56y^2 = (x-8y)(x+7y)$

How do you factor x^2-xy-56y^2x^2-xy-56y^2?