How do you factor $x^{2} - y^{2} + z^{2} - 2 x z$ $x^2 - y^2 + z^2 - 2xz$ ?

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How do you factor $x^{2} - y^{2} + z^{2} - 2 x z$ $x^2 - y^2 + z^2 - 2xz$ ?

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Answer 1 · 2016-05-21T01:52:20

It is

$x^{2} - y^{2} + z^{2} - 2 x z = (x^{2} - 2 x z + z^{2}) - y^{2} = {(x - z)}^{2} - y^{2} = (x - z + y) \cdot (x - z - y)$ $x^2 - y^2 + z^2 - 2xz=(x^2-2xz+z^2)-y^2= (x-z)^2-y^2=(x-z+y)*(x-z-y)$

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How do you factor $x^{2} - y^{2} + z^{2} - 2 x z$ $x^2 - y^2 + z^2 - 2xz$ ?

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How do you factor $x^{2} - y^{2} + z^{2} - 2 x z$ $x^2 - y^2 + z^2 - 2xz$ ?